0.2x^2-100x+1500=0

Solution for 0.2x^2-100x+1500=0 equation:

0.2x^2-100x+1500=0

a = 0.2; b = -100; c = +1500;
Δ = b2-4ac
Δ = -1002-4·0.2·1500
Δ = 8800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8800}=\sqrt{400*22}=\sqrt{400}*\sqrt{22}=20\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20\sqrt{22}}{2*0.2}=\frac{100-20\sqrt{22}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20\sqrt{22}}{2*0.2}=\frac{100+20\sqrt{22}}{0.4}
$